sql – 连接多行
发布时间:2021-02-06 14:25:34 所属栏目:MsSql教程 来源:网络整理
导读:我正在使用Microsoft SQL Server 2005. 我想我需要一个子查询. 我正在为每个客户寻找一(1)行,其中AvailableAction字段是每个客户的所有操作的串联. use tempdbGOIF DB_ID('myDatabase') IS NOT NULL DROP DATABASE myDatabasegoCREATE DATABASE myDatabase GO
我正在使用Microsoft SQL Server 2005. 我想我需要一个子查询. 我正在为每个客户寻找一(1)行,其中AvailableAction字段是每个客户的所有操作的串联. use tempdb GO IF DB_ID('myDatabase') IS NOT NULL DROP DATABASE myDatabase go CREATE DATABASE myDatabase GO USE myDatabase GO create table Cust( CustID Int Identity Primary Key,CustName Varchar(255) ) GO INSERT INTO Cust(CustName) values('One') INSERT INTO Cust(CustName) values('Two') GO CREATE TABLE Action( ActionID Int Identity(101,1) Primary Key,ActionName Varchar(128) ) GO INSERT INTO Action(ActionName) VALUES('Insert') INSERT INTO Action(ActionName) VALUES('Update') INSERT INTO Action(ActionName) VALUES('Delete') INSERT INTO Action(ActionName) VALUES('Print') GO create table CustAction( CustActionID Int Identity Primary Key,CustID Int,ActionID Int ) GO INSERT INTO CustAction(CustID,ActionID) VALUES(1,101) INSERT INTO CustAction(CustID,102) INSERT INTO CustAction(CustID,ActionID) VALUES(2,103) GO SELECT Cust.CustID,CustName,ActionName FROM CustAction JOIN Cust ON CustAction.CustID = Cust.CustID JOIN Action ON CustAction.ActionID = Action.ActionID GO SELECT Cust.CustID,'<option value="' + CAST(Action.ActionID AS Varchar) + '">' + ActionName + '</option>' AS AvailableAction FROM CustAction JOIN Cust ON CustAction.CustID = Cust.CustID JOIN Action ON CustAction.ActionID = Action.ActionID 我希望输出为: CustID AvailableAction 1 <option value="101">Insert</option><option value="102">Update</option> 2 <option value="102">Update</option><option value="103">Delete</option> 解决方法2005年SELECT CustID,(SELECT ca.ActionID [@value],ActionName [text()] FROM dbo.CustAction ca INNER JOIN dbo.Action ON ca.ActionID = Action.ActionID WHERE ca.CustID = c.CustID FOR XML PATH('option'),TYPE) AvailableAction FROM dbo.Cust c 我不认为你能用FOR XML EXPLICIT得到这个,所以如果这是2000你就不走运了(就简单的解决方案而言). (编辑:瑞安网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |